1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Mathematics
Director Circle
The equation ...
Question
The equation of director circle of the circle
x
2
+
y
2
=
a
2
is
A
x
2
+
y
2
=
4
a
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x
2
+
y
2
=
√
2
a
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x
2
+
y
2
−
2
a
2
=
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
x
2
+
y
2
−
2
a
2
=
0
Director circle has its radius
√
2
times that of radius of the given circle. Hence equation is
x
2
+
y
2
=
2
a
2
.
Suggest Corrections
1
Similar questions
Q.
The equation of the circle drawn with the two foci of
x
2
a
2
+
y
2
b
2
=
1
as the end-points of a diameter is
(a) x
2
+ y
2
= a
2
+ b
2
(b) x
2
+ y
2
= a
2
(c) x
2
+ y
2
= 2a
2
(d) x
2
+ y
2
= a
2
− b
2
Q.
If the curve
x
2
4
+
y
2
=
1
and
x
2
a
2
+
y
2
=
1
for suitable values of
′
a
′
cut on four concyclic points, the equation of the circle passing through these points is
Q.
The locus of the point of intersection of two perpendicular tangents to the circle
x
2
+
y
2
=
a
2
is
Q.
A circle is concentric with the circle
x
2
+
y
2
−
6
x
+
12
y
+
15
=
0
and has area double of its area. The equation of the circle is
Q.
The equation of the circle concentric with x
2
+ y
2
− 3x + 4y − c = 0 and passing through (−1, −2) is
(a) x
2
+ y
2
− 3x + 4y − 1 = 0
(b) x
2
+ y
2
− 3x + 4y = 0
(c) x
2
+ y
2
− 3x + 4y + 2 = 0
(d) none of these
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Tangent to a Circle
MATHEMATICS
Watch in App
Explore more
Director Circle
Standard VIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app