The equation of directrix of the parabola $y^{2} = 10 x$ is?

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Solution

$\begin{matrix} y^{2} = 10 x c o m p a r e w i t h y^{2} = 10 8 a = 10 ∴ a = \frac{10}{4} = \frac{5}{2} R q u a t i o n o f d i r e c t i o n i s n = - a \Rightarrow n = \frac{- 5}{2} 2 n + 5 = 0 I t i s t h e e q u a t i o n o f d i r e c t r i x . \end{matrix}$

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