The equation of displacement of a harmonic oscillator is x=3sinωt+4cosωt. The amplitude of the particles will be
A
1
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B
5
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C
7
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D
12
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Solution
The correct option is B 5 In the equation of superposition of SHMs or Harmonic oscillator, x=asinωt+bsinωt, the resultant amplitude is given by A=√a2+b2. Substituting a=3 and b=4, we get final answer as Option B, i.e. 5