Question

The equation of displacement of a harmonic oscillator is $x=3\sin \omega t+4\cos \omega t$. The amplitude of the particles will be

• A. 1
• B. 5
• C. 7
• D. 12

Answer 1

The correct option is B 5

In the equation of superposition of SHMs or Harmonic oscillator, $x=asin\omega t+bsin\omega t$, the resultant amplitude is given by $A=\sqrt{a^2+b^2}$. Substituting a=3 and b=4, we get final answer as Option B, i.e. 5