The equation of displacement of a particle is $x (t) = 5 t^{2} - 7 t + 3$ . The acceleration at the moment when its velocity becomes $5 m / s e c$ is :

8 m / s e c^{2}

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3 m / s e c^{2}

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7 m / s e c^{2}

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10 m / s e c^{2}

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Solution

The correct option is D $10 m / s e c^{2}$
$x = 5 t^{2} - 7 t + 3$
$\Rightarrow$ Velocity, $v = \frac{d x}{d t} = 10 t - 7$
Acceleration, $\frac{d^{2} x}{d t^{2}} = 10$

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The equation of displacement of a particle is x(t)=5t2−7t+3. The acceleration at the moment when its velocity becomes 5m/sec is :

The correct option is D 10m/sec2x=5t2−7t+3 ⇒ Velocity, v=dxdt=10t−7 Acceleration, d2xdt2=10

The equation of displacement of a particle is $x (t) = 5 t^{2} - 7 t + 3$ . The acceleration at the moment when its velocity becomes $5 m / s e c$ is :

The correct option is D $10 m / s e c^{2}$
$x = 5 t^{2} - 7 t + 3$
$\Rightarrow$ Velocity, $v = \frac{d x}{d t} = 10 t - 7$
Acceleration, $\frac{d^{2} x}{d t^{2}} = 10$