The equation of displacement of two waves are given as y1 - 10 sin 3- t - - -3 y2 - 5 sin 3- t - -3 cos 3 - t- then what is the ratio of their amplitude-

You visited us 68 times! Enjoying our articles? Unlock Full Access!

Sinusoidal Wave

The equation ...

Question

The equation of displacement of two waves are given as
$y_{1} = 10 s i n (3 π t + π / 3)$
$y_{2} = 5 (s i n 3 π t + \sqrt{3} c o s 3 π t)$ , then what is the ratio of their amplitude;

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

y_{1} = 10 s i n (3 π t + \frac{π}{3})

y_{2} = 5 (s i n 3 π t + \sqrt{3} c o s 3 π t)

y_{1} = 10 sin (3 π t + \frac{π}{3}), y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t)

Y_{1} = 10 sin (π t + π / 3)

Y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t

Y_{1} = 10 sin (3 π t + \frac{π}{4})

Y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t)

y_{1} = 10 sin (3 π t + π / 4)

y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t)

Join BYJU'S Learning Program