$T h e e q u a t i o n o f f o u r c i r c l e s a r e (x + a)^{2} + (y + a)^{2} = a^{2} . T h e r a d i u s o f a c i r c l e t o u c h i n g a l l t h e f o u r c i r c l e s i s$

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Solution

The correct option is A

$R a d i u s o f s m a l l e s t c i r c l e i s$

$r + a = a \sqrt{2} r = a \sqrt{2} - a A n o t h e r c i r c l e \Rightarrow r = a \sqrt{2} + a$

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