wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of hyperbola conjugate to the hyperbola 2x2+3xy−2y2−5+5y+2=0 is

A
2x2+3xy2y25x+5y8=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+3xy2y25x+5y+8=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x2+3xy2y2+5x5y8=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2x2+3xy2y25x+5y8=0
Let the given hyperbola be H=2x2+3xy2y25x+5y+2=0

Thus the pair of asymptotes be A=2x2+3xy2y25x+5y+λ=0

Pair of straight line has Δ=0
Δ=abc+2fghaf2bg2ch2=0

where,
a=2
b=2
c=λ
f=52
g=52
h=32

Thus, λ=3

A=2x2+3xy2y25x+5y3=0

Since H+C=2A Where C be the equation of conjugate hyperbola

C=2AH
So,the equation of conjugate hyperbola be C=2x2+3xy2y25x+5y8=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon