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Question

The equation of hyperbola whose axes are the coordinates axes, one vertex is (3,0) and eccentricity is 52 is

A

x292y227=1

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B
x29y227=1
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C
x215y226=1
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D
x293y227=1
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Solution

The correct option is A

x292y227=1


e2=52
1+b2a2=52b2=32a2(1)
Distance between center and vertex =a=3
Putting in (1) we get,
b2=32(9)b2=272
x29y2272=1
x292y227=1

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