The equation of line having slope -12 and passing though 1-4 is

The correct option is A x+2y 7=0 Given point (1,4) The slope of line is 12 The equation of line is y 4= 12(x 1) 2(y 4) = 1 x 2y ...

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Standard VIII

Mathematics

Construction of a Rectangle When One Side and One Diagonal Are Given.

The equation ...

Question

The equation of line having slope $\frac{- 1}{2}$ and passing though $(1, 4)$ is

x + 2 y - 7 = 0

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x + 2 y = 0

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x - 4 y = 7

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2 y = x + 3

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Solution

The correct option is A $x + 2 y - 7 = 0$

Given point $(1, 4)$

The slope of line is $\frac{- 1}{2}$

The equation of line is $y - 4 = \frac{- 1}{2} (x - 1)$

$⟹ 2 (y - 4) = 1 - x$

$⟹ 2 y - 8 = 1 - x$

$⟹ x + 2 y - 7 = 0$

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The equation of line having slope −12 and passing though (1,4) is

The correct option is A x+2y−7=0Given point (1,4)The slope of line is −12The equation of line is y−4=−12(x−1)⟹2(y−4)=1−x⟹2y−8=1−x⟹x+2y−7=0

The equation of line having slope $\frac{- 1}{2}$ and passing though $(1, 4)$ is

The correct option is A $x + 2 y - 7 = 0$

Given point $(1, 4)$

The slope of line is $\frac{- 1}{2}$

The equation of line is $y - 4 = \frac{- 1}{2} (x - 1)$

$⟹ 2 (y - 4) = 1 - x$

$⟹ 2 y - 8 = 1 - x$

$⟹ x + 2 y - 7 = 0$