The equation of line passing through (5, 4) and perpendicular to the line 3x - 2y - 5 = 0 is ___________.

2x + 3y + 9 = 0

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3x - 2y - 7 = 0

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2x + 3y - 22 = 0

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2x - 3y + 2 = 0

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Solution

The correct option is C 2x + 3y - 22 = 0
The required line is perpendicular to $3 x - 2 y - 5 = 0$

$3 x - 2 y - 5 = 0$

$2 y = 3 x - 5$

$y = \frac{3}{2} x - \frac{5}{2}$

Hence slope $= \frac{3}{2}$

Thus, slope of required line $= \frac{- 2}{3}$

Thus, equation of required line is :

$y - 4 = \frac{- 2}{3} (x - 5)$

$3 y - 12 = - 2 x + 10$

$2 x + 3 y - 22 = 0$

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Similar questions

Solve the following system of linear equations graphically and shade the region between the two lines and x-axis;

(i) 2x + 3y = 12,

x - y = 1

(ii) 3x + 2y - 4 = 0,

2x - 3y - 7 = 0

(iii) 3x + 2y - 11 = 0

2x - 3y + 10 = 0

The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 14

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