The correct option is C x−22=y+13=z−1−1
Equation of line passing through point A(x1,y1,z1) and parallel to vector →B=a^i+b^j+c^k is given by :
x−x1a=y−y1b=z−z1c
Given : (a,b,c)=(2,3,−1) and (x1,y1,z1)=(2,−1,1)
So, equation of line is given by
x−22=y+13=z−1−1