The equation of line passing through the point of intersection of the lines4x-3y-1=0 and 5x-2y-3=0 and parallel to the line 2y-3x+2=0, is

x-3y=1

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3x-2y=1

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2x-3y=1

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2x-y=1

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Solution

The correct option is B 3x-2y=1
The point of intersection of the lines is (1, 1). The equation of line parallel to 2y-3x+2=0 is 2y-3x+k=0. It also passes through (1, 1), therefore k=1. Hence the required equation is 2y-3x+1=0 or 3x-2y=1.

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