The equation of line perpendicular to $x - 2 y + 1 = 0$ and passing through $(1, 2)$ is

3 x - 8 y + 6 = 0

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2 x + y = 4

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3 x - 5 y + 1 = 0

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5 x + 3 y = 0

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Solution

The correct option is B $2 x + y = 4$
line perpendicular to $a x + b y + c_{1} = 0 \Rightarrow b x - a y + c_{2} = 0$

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Similar questions

The equation of the line passing through $(1, 5)$ and perpendicular to the line $3 x - 5 y + 7 = 0$ is

P (1, 2)

3 x + 2 y - 5 = 0

2 x - 5 y + 1 = 0

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