The equation of line that passes through $(10, - 1)$ and is perpandicular to $y = \frac{x}{4} - 2$ is

4 x + y = 39

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2 x + y = 19

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x + y = 9

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x + 2 y = 8

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Solution

The correct option is C $4 x + y = 39$
Required line is perpendicular to the line having slope $= \frac{1}{4}$
So, slope of required line $= - 4$

Line passing through $(10, - 1)$

=> Required line $= y - (- 1) = - 4 (x - 10)$

=> $4 x + y = 39$

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