Question

The equation of line whose slope is $\frac{1}{3}$ and $x-$ intercept is $4$ will be

• A. $x-3y+12=0$
• B. $x-6y-2=0$
• C. $4x-y-16=0$
• D. $x-3y-4=0$

Answer 1

The correct option is D $x-3y-4=0$

If the $x-$ intercept of line is $4$, then line passes through $(4,0)$
Equation of line is
$y-0=\frac{1}{3}(x-4)$
$\Rightarrow y=\frac{1}{3}x-\frac{4}{3}$
$\Rightarrow x-3y-4=0$