The equation of line with sloe $3$ and passing through $(- 2, 5)$

3x-y+11=0

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3x-y=8

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x-3y=11

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x+3y=9

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Solution

The correct option is A 3x-y+11=0
The slope of line is $3$
The point is $(- 2, 5)$
The equation is given as $(y - 5) = 3 (x + 2) y - 5 = 3 x + 6 3 x - y + 11 = 0$

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