The equation of line with slope $1$ and passing through origin

y=x

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x+y=0

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y=-x

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None.

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Solution

The correct option is A y=x
The slope is $1$
The point is $(0, 0)$
The equation is $y - 0 = 1 (x - 0) y = x$

Suggest Corrections

Similar questions

(x^{'}, y^{'})

x x^{'} + y y^{'} = a^{2}

\frac{x x^{'}}{a^{2}} + \frac{y y^{'}}{b^{2}} = 1

x^{'} y + x y^{'} = a^{2}

\frac{1}{2}

\frac{d y}{d x} - y

The equation of the line passing through origin with slope = 1 is:

(- 4, 3)

(\frac{1}{2})

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