MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polarisation

The equation ...

Question

The equation of Mohr's circle is given by $(σ - 4)^{2} + τ^{2} = 9$ where $σ$ is the normal stress and $τ$ is the shear stress. The maximum shear stress is units. ,

3

Open in App

Solution

The correct option is A 3
Given: $(σ - 4)^{2} + τ^{2} = 9$
Centre of the circle is (4,0) and radius is 3 units.

So, $τ_{m a x} = 3$ units.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Consider the following statements?
1. The maximum shear stress is one half of the normal stress in the case of uniaxial stress field.
2. In biaxial stress field, acted upon by normal stresses unaccompanied by shear stresses, the maximum shear stress is any one of the normal stresses.
3. The Mohr's stress circle will be tangential to the vertical axis in the case of uniaxial stress field.
Which of the above statements are correct?

Q. The stress state at a point in a material under plane stress condition is equi-biaxial tension with a magnitude of 10 MPa. If one unit on the

σ - τ

plane is 1 MPa, the Mohr's circle representation of the state-of-stress is given by

Q. A specimen is subjected to a pure shear stress regime of intensity

τ

. The resulting tensile and compressive stresses

σ

, which occur on planes inclined at 45° to the direction of the shear stresses, would be

$σ_{x}, σ_{y} a n d τ_{x y}$ and normal and shear stresses on the x and y faces. What is the radius of Mohr's circle in terms of these stresses?

Q. A thin cylindrical tube with closed ends is subjected to:
1. Longitudinal stress

σ_{1} = 14 N / m m^{2}

σ_{2} = 2 N / m m^{2}

3. Shearing stress

τ = 8 N / m m^{2}

Then the maximum shearing stress is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Polarization I

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon