The equation of motion of a particle executing simple harmonic motion is a+16π2x=0. In this equation, a is linear acceleration in m/s2 of the particle at displacement x in m. The time period of this simple harmonic motion is
A
14s
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B
12s
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C
13s
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D
15s
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Solution
The correct option is B12s Given: a+16π2x=0 ⇒a=−16π2x On comparing it with the acceleration of SHM, a=−ω2x We get, ω2=16π2 ⇒ω=4π We know, time period of SHM, T=2πω ⇒T=2π4π=12s