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Question

The equation of motion of a particle executing simple harmonic motion is a+16π2x=0. In this equation, a is linear acceleration in m/s2 of the particle at displacement x in m. The time period of this simple harmonic motion is

A
14 s
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B
12 s
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C
13 s
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D
15 s
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Solution

The correct option is B 12 s
Given:
a+16π2x=0
a=16π2x
On comparing it with the acceleration of SHM,
a= ω2x
We get, ω2=16 π2
ω=4 π
We know, time period of SHM,
T=2 πω
T=2 π4 π=12 s

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