The equation of motion of a particle executing simple harmonic motion is a+16π2x=0. In this equation, a is the linear acceleration (in m/s2) of the particle at a displacement x (in meter). The time period in simple harmonic motion is
A
14sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B12sec a=−16π2x Standard equation of SHM is: a=−ω2x Hence, comparing two equations, we get ω=4π and T=2πω=2π4π=12sec