The equation of motion of a particle in S.H.M. is given by $a = - B \times x$ ,where a is the acceleration, B is a constant and x is displacement. The period of oscillation of the particle is:

π \sqrt{B}

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π / B

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π / \sqrt{B}

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π B

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Solution

The correct option is C 2 $π / \sqrt{B}$
$a = - B x$
so, $B = ω^{2}$ $(∴ a = - ω^{2} x)$
$T = \frac{2 π}{ω}$
$= \frac{2 π}{\sqrt{B}}$
$s o, t i m e p e r i o d o f o s c i l l a t i o n s = \frac{2 π}{\sqrt{B}}$

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The equation of motion of a particle in S.H.M. is given by a=−B×x ,where a is the acceleration, B is a constant and x is displacement. The period of oscillation of the particle is:

The correct option is C 2π/√Ba=−Bxso, B=ω2 (∴a=−ω2x)T=2πω=2π√Bso,time period of oscillations=2π√B

The equation of motion of a particle in S.H.M. is given by $a = - B \times x$ ,where a is the acceleration, B is a constant and x is displacement. The period of oscillation of the particle is:

The correct option is C 2 $π / \sqrt{B}$
$a = - B x$
so, $B = ω^{2}$ $(∴ a = - ω^{2} x)$
$T = \frac{2 π}{ω}$
$= \frac{2 π}{\sqrt{B}}$
$s o, t i m e p e r i o d o f o s c i l l a t i o n s = \frac{2 π}{\sqrt{B}}$