The equation of motion of a particle is x-3 cos 0-45 t- - 4 m- Its maximum acceleration is

The correct option is D 0.60 ms 2 Maximum acceleration=ω2r= (0.45)2x3=0.60ms 2 ...

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Standard VIII

Physics

Acceleration

The equation ...

Question

The equation of motion of a particle is x= 3cos(0.45t+π/4)m. Its maximum acceleration is

0.45 ms^-2

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0.50 ms^-2

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0.55 ms^-2

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0.60 ms^-2

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Solution

The correct option is D
0.60 ms^-2

Maximum acceleration=ω²r= (0.45)²x3=0.60ms^-2

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The equation of motion of a particle is x= 3cos(0.45t+π/4)m. Its maximum acceleration is

The correct option is D 0.60 ms-2 Maximum acceleration=ω2r= (0.45)2x3=0.60ms-2

The correct option is D
0.60 ms^-2

Maximum acceleration=ω²r= (0.45)²x3=0.60ms^-2