Question

The equation of motion of a particle moving along a straight line is given by $s=63t-6t^2-t^{3}cm$.Find its velocity after 2s and the distance covered by it before coming to rest

Answer 1

$v=\frac{ds}{dt}$ $s=63t-6t^2-t^3$

$v=63-12t-3t^2$

at $t=2$

$v=27m/s$

at $t=0$ $s=0$

$t=2$ $s=63\left(2\right)-6(2{)}^2-(2{)}^3$

$=94cm$