The equation of normal to the curve $2 y = 3 - x^{2}$ at the point $(1, 1)$

x + y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + y = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $x - y = 0$
The curve is $2 y = 3 - x^{2}$

Slope $= 2 y^{'} = - 2 x$ or $\frac{d y}{d x} = - x$

Slope at $(1, 1)$ is $\frac{d y}{d x} = - 1$

Equation of normal is $y - 1 = \frac{- 1}{- 1} (x - 1)$

$\Rightarrow x - 1 - y + 1 = 0$

$\Rightarrow x - y = 0$ is the equation of the normal.

Suggest Corrections

Similar questions

Q. The normal at the point (1, 1) on the curve 2 y + x 2 = 3 is (A) x + y = 0 (B) x − y = 0 (C) x + y + 1 = 0 (D) x − y = 1

The normal at the point (1, 1) on the curve 2y + x² = 3 is

(A) x + y = 0 (B) x − y = 0

Choose the correct answer in the following question:

The normal at the point (1, 1) on the curve $2 y + x^{2} = 3$ is

(a) x + y = 0 (b) x - y = 0 (c) x + y + 1 = 0 (d) x - y + 1 = 0

Q. The equation of the normal to the curve

y = 2 x^{2} + 3 sin x

at x = 0 is .

Q. The equation of the normal to the curve y = x(2 − x) at the point (2, 0) is

(a) x − 2y = 2
(b) x − 2y + 2 = 0
(c) 2x + y = 4
(d) 2x + y − 4 = 0

Join BYJU'S Learning Program

The equation of normal to the curve 2y=3−x2 at the point (1,1)

The correct option is D x−y=0The curve is 2y=3−x2Slope=2y′=−2x or dydx=−xSlope at (1,1) is dydx=−1Equation of normal is y−1=−1−1(x−1)⇒x−1−y+1=0⇒x−y=0 is the equation of the normal.

The equation of normal to the curve $2 y = 3 - x^{2}$ at the point $(1, 1)$