Question

# The equation of normal to the curve $$2y=3-{ x }^{ 2 }$$ at the point $$\left(1,1\right)$$

A
x+y+1=0
B
x+y=0
C
xy+1=0
D
xy=0

Solution

## The correct option is D $$x-y=0$$The curve is $$2y=3-{x}^{2}$$Slope$$=2{y}^{\prime}=-2x$$ or $$\dfrac{dy}{dx}=-x$$Slope at $$\left(1,1\right)$$ is $$\dfrac{dy}{dx}=-1$$Equation of normal is $$y-1=\dfrac{-1}{-1}\left(x-1\right)$$$$\Rightarrow x-1-y+1=0$$$$\Rightarrow x-y=0$$ is the equation of the normal.Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More