Equation of Tangent at a Point (x,y) in Terms of f'(x)
The equation ...
Question
The equation of normal to the curve y=tanx at the point (0,0) is -
A
x+y=0
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B
x−y=0
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C
x+2y=0
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D
None of these
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Solution
The correct option is Ax+y=0 y=tanx ⇒dydx=secx ⇒∴(dydx)(0,0)=1=m (say) ∴ Slope of normal at the given point is =−1m=−1 Therefore, equation of normal is, (y−0)=−1(x−0) ⇒x+y=0 Hence, option 'A' is correct.