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Question

The equation of normal to the curve y=∣∣x2−|x|∣∣ at x=−2 is

A
3y=2x+10
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B
3y=x+8
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C
2y=x+6
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D
2y=3x+10
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Solution

The correct option is C 3y=x+8
y=x2x=(x )(x1)
At x=2,y=2

dydx=xxx1+x1x1x2x

(dydx)x=2=12=3

The equation of normal is y=x3+(2+23)

3y=x+8

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