wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

The equation of normal to the hyperbola xy=25 at the point P(2) in the first quadrant is

A
8x+2y75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
8x+2y+75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
C
8x2y75=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
8x2y+75=0
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is C 8x2y75=0
Given, xy=25
P(2)t=2
c2=25c=5
as it lies in first quadrant
Equation of normal to the hyperbola xy=c2 at the point P(t) is xt3ytct4+c=0
Put the values of t and c
x(2)3y(2)c(2)4+5=0
8x2y16×5+5=0
8x2y75=0
Hence, the correct answer is Option a.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Error and Uncertainty
Watch in App
Join BYJU'S Learning Program
CrossIcon