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Question

The equation of one of the line represented by the equation pq(x2y2)+(p2q2)xy=0, is

A
px+qy=0
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B
pxqy=0
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C
p2x+q2y=0
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D
d2xp2y=0
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Solution

The correct option is B pxqy=0
Given that
the equation
pq(x2y2)+(p2q2)xy=0
pqx2pqy2+p2xyq2xy=0
pqx2+p2xypqy2q2xy=0
px(qx+py)qy(py+qx)=0
(qx+py)(pxqy)=0
now,
qx+py=0,pxqy=0
Hence,
pxqy=0
this is the answer.

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