The equation of parabola, whose axis is parallel to $y -$ axis and which passes through points $(0, 2), (- 1, 0)$ and $(1, 6)$ is

y = x^{2} + 3 x + 2

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y = x^{2} + 3 x - 2

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x^{2} + 3 y + 2 = 0

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y^{2} + 3 x + 2 = 0

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Solution

The correct option is A $y = x^{2} + 3 x + 2$
General equation of such parabola is $y = A x^{2} + B x + C \dots (1)$
Since eqn. $(1)$ passes through $(0, 2), (- 1, 0)$ and $(1, 6),$ then we have
$C = 2 \dots (2) A - B + C = 0 \dots (3) A + B + C = 6 \dots (4)$
From $(2), (3)$ and $(4),$ we get
$A = 1, B = 3, C = 2$
$∴$ Equation of parabola is $y = x^{2} + 3 x + 2$

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