The equation of parabola, whose axis is parallel to y−axis and which passes through points (0,2),(−1,0) and (1,6) is
A
y=x2+3x+2
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B
y=x2+3x−2
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C
x2+3y+2=0
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D
y2+3x+2=0
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Solution
The correct option is Ay=x2+3x+2 General equation of such parabola is y=Ax2+Bx+C⋯(1)
Since eqn. (1) passes through (0,2),(−1,0) and (1,6), then we have C=2⋯(2)A−B+C=0⋯(3)A+B+C=6⋯(4)
From (2),(3) and (4), we get A=1,B=3,C=2 ∴ Equation of parabola is y=x2+3x+2