The equation of parabola whose focus is -3-0 and directrix x-5-0 is-A- y2-4 xB- y2-4x-1C- y2-4x-4D- y2-4x-16

The correct option is C y2 = 4(x + 4) The required equation of parabola is: ...

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Standard XII

Mathematics

Graph of Quadratic Expression

The equation ...

Question

The equation of parabola whose focus is (– 3, 0) and directrix x + 5 = 0 is:

y² = 4x

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y² = 4(x + 1)

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y² = 4(x + 4)

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y² = 4(x + 16)

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Solution

The correct option is C
y² = 4(x + 4)

The required equation of parabola is:

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