The equation of parabola whose vertex and focus are (0, 4) and (0,2) respectively, is
A
y2−8x=32
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B
y2+8x=32
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C
x2+8y=32
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D
x2−8y=32
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Solution
The correct option is Cx2+8y=32 Vertex (0, 4); focus (0, 2); ∴a=2
Hence it is an upward facing parabola. So the equation of the parabola will be of the form x2=−4ay
Hence parabola is (x−0)2=−4.2(y−4)i.e.,x2+8y=32