The equation of parabola $x^{2} = - 4 a y$ when shifted along x-axis at $(h, 0)$ , where $h$ is constant is.

{(x - h)}^{2} = - 4 a y

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{(x + h)}^{2} = - 4 a y

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x^{2} = - 4 a (y - h)

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Solution

The correct option is A ${(x - h)}^{2} = - 4 a y$
Given equation of parabola is $x^{2} = - 4 a y$ having vertex at origin.

When the parabola $x^{2} = - 4 a y$ is shifted along x-axis, then the new equation of parabola is given by $(x - h)^{2} = - 4 a y .$

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