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Byju's Answer
Standard XII
Mathematics
Perpendicular Distance of a Point from a Line
The equation ...
Question
The equation of perpendicular bisectors of sides
A
B
,
B
C
of
Δ
A
B
C
are
x
−
y
−
5
=
0
and
x
+
2
y
=
0
respectively. If
A
≡
(
1
,
−
2
)
,
C
≡
(
α
,
β
)
, then
α
+
β
is equal to
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Solution
B
(
h
,
k
)
is the image of
A
with respect to
x
−
y
−
5
=
0
So,
h
−
1
1
=
k
+
2
−
1
=
−
2
(
1
+
2
−
5
2
)
⇒
h
−
1
1
=
k
+
2
−
1
=
2
⇒
(
h
,
k
)
=
(
3
,
−
4
)
Now,
C
is the image of
B
with respect to
x
+
2
y
=
0
So,
α
−
3
1
=
β
+
4
2
=
−
2
(
3
−
8
1
+
4
)
⇒
α
=
5
,
β
=
0
⇒
α
+
β
=
5
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22
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Perpendicular Distance of a Point from a Line
Standard XII Mathematics
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