MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Intercept Made by Circle on Axes

The equation ...

Question

The equation of perpendicular bisectors of the sidesAB and AC of a triangle ABC are x- y +5 = 0 and x + 2y =0 respectively. If the point A is (1,- 2), thenthe equation of line BC is

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. The equation of the perpendicular bisectors of the sides AB and AC of triangle ABC an

x - y + 5 = 0

x + 2 y = 0

, respectively. If the point A is (1, -2) find the equation of the line BC.

Q. The equation of the perpendicular bisector of the sides

A B

A C

A B C

x - y + 5 = 0

x + 2 y = 0

respectively. If the point

A

(1, - 2)

, the equation of the line

B C

Q. The equation of the perpendicular bisector of the sides

A B

A C

△ A B C

x - y + 5 = 0

x + 2 y = 0,

respectively. If the point

A

(1, - 2)

then the equation of the line

B C

Q. The equation of the perpendicular bisectors of the sides AB and AC of a

Δ

x - y + 5 = 0

x + 2 y = 0

respectively. If the point A is

(1, - 2)

, then the equation of the line BC is?

Q. The equation of the prependicular bisectors of the sides AB & AC of a triangle ABC are

x - y + 5 = 0

x + 2 y = 0

, respectively. If the point A is (1, -2) find the equation of the line BC.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Intercepts Made by Circles on the Axes

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Intercept Made by Circle on Axes

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon