Question

The equation of plane through the intersection of planes (x+y+z =1) and (2x +3y - z+4) =0 is

• A. x(1+2k)+y(1-3k)+z(1-k)+(-1+4k) =0
• B. x(1+2k) +y(1+3k)+z(1-k) +(-1 - 4k)= 0
• C. x ( 1-2k) + y(1+3k) +z(1-k) +(-1+4k) =0
• D. x(1 + 2k) + y(1 + 3k) + z(1 - k) + (-1 + 4k) =0

Answer 1

The correct option is D

x(1 + 2k) + y(1 + 3k) + z(1 - k) + (-1 + 4k) =0

The equation of the plane which passes through the point of intersection of the two given planes is given by

x + y + z -1 + k ( 2x + 3y - z + 4) = 0

x(1 + 2k) + y(1 + 3k) + z(1 - k) + (-1 + 4k) =0