Question

The equation of projectile is $y=16x-\frac{x^2}{4}$ the horizontal range is:

• A. $16$ m
• B. $8$ m
• C. $64$ m
• D. $12.8$ m

Answer 1

The correct option is C $64$ m

horizontal range is when the parabola cross the axis. it is going to cut x -axis at two points and the distance between them is the range.

$y=16x-\frac{x^2}{4}$

$0=16x-\frac{x^2}{4}$

$x_1=0$ and $x_2=64$ are two roots of above equation

therefore range is $R=x_2-x_1=64-0=64m$