Question

The equation of projectile is $y=16x-\frac{5x^2}{4}$ . The horizontal range is

• A. 16 m
• B. 8 m
• C. 3.2 m
• D. 12.8 m

Answer 1

The correct option is D

12.8 m

Standard equation of projectile motion $y=xtan\theta [1-\frac{x}{R}]$

Given equation : $y=16x-\frac{5x^2}{4}ory=16x[1-\frac{x}{\frac{64}{5}}]$

By comparing above equations $R=\frac{64}{5}=12.8m$