Question

The equation of simple harmonic wave is given by $y=5$sin $\frac{5}{2}(100t-x)$, where $x$ and $y$ are in meter and time is in second. The time period of the wave (in second) will be.

• A. $0.04$
• B. $0.06$
• C. $0.01$
• D. $0.05$

Answer 1

The correct option is B $0.06$

$y=5$sin $\frac{\pi }{2}(100t-x)$
$y=A$sin$(\omega t-kx)$

$\omega =\frac{2\pi }{T}$

$T=\frac{2\pi }{100}$

$\Rightarrow T=0.06$
Hence, the correct option is $\left(B\right)$