The equation of state of a gas is given by $(P + \frac{a T^{2}}{V}) V^{c} = (R T + b)$ , where a, b, c and R are constants. The isotherms can be represented by $P = A V^{m} - B V^{n}$ , where A and B depend only on temperature and

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Solution

The correct option is A

$(P + \frac{a T^{2}}{V}) V^{c} = R T + b P + \frac{a T^{2}}{V} = \frac{R T}{V^{c}} + \frac{b}{V^{c}} P = (R T + b) V^{- c} - a T^{2} V^{- 1} Comparing with P = A V^{m} - B V^{n} m = - c; n = - 1$

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The equation of state of a gas is given by (P+aT2V)Vc=(RT+b), where a, b, c and R are constants. The isotherms can be represented by P=AVm−BVn , where A and B depend only on temperature and

The correct option is A (P+aT2V)Vc=RT+bP+aT2V=RTVc+bVcP=(RT+b)V−c−aT2V−1Comparing withP=AVm−BVnm=−c; n=−1

The equation of state of a gas is given by $(P + \frac{a T^{2}}{V}) V^{c} = (R T + b)$ , where a, b, c and R are constants. The isotherms can be represented by $P = A V^{m} - B V^{n}$ , where A and B depend only on temperature and

The correct option is A

$(P + \frac{a T^{2}}{V}) V^{c} = R T + b P + \frac{a T^{2}}{V} = \frac{R T}{V^{c}} + \frac{b}{V^{c}} P = (R T + b) V^{- c} - a T^{2} V^{- 1} Comparing with P = A V^{m} - B V^{n} m = - c; n = - 1$