The equation of state of a gas is given by P(V−b)=nRT. If 1mole of a gas is isothermally expanded from volume V and 2V, the work done during the process is
A
RT ln(2V−bV−b)
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B
RT ln(V−bV)
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C
RT ln(V−b2V−b)
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D
RT ln(VV−b)
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Solution
The correct option is ART ln(2V−bV−b) Given, equation of state of gas P(V−b)=nRT
Initial volume (Vi)=V
Final volume (Vf)=2V
Work done in an isothermal process, W=∫VfViPdV W=∫2VVnRTV−bdV=nRTln(V−b)|2VV
For 1mole, W=RT ln(2V−bV−b)