Question

The equation of stationary wave along a stretched string is given by $y=5sin\frac{\pi x}{3}cos40\pi t$ where x and y are in centimetre and t in second. The separation between two adjacent anti nodes is :

• A. 1 cm
• B. 2 cm
• C. 3 cm
• D. 1.5 cm

Answer 1

The correct option is C 3 cm

Given $y=5sin\frac{\pi x}{3}cos40\pi t$
Comparing with standing wave equation, we get $\Rightarrow \lambda =6cm.$
$\therefore$ The separation between adjacent nodes
​$=\frac{\lambda }{2}=3cm$