Question

The equation of tangent at $(1,2)$ on the curve $x^2=2y$

Answer 1

Given point $(1,2)$

Given equation is $x^2=2y$

Slope of tangent at given point is given as $2x=2\frac{dy}{dx}\frac{dy}{dx}=x{\frac{dy}{dx}|}_{(1,2)}=1$

The equation of tangent is given as $(y-2)=1(x-1)x-y+1=0$