The equation of tangent to the circle $x^{2} + y^{2} = 13$ at $(2, 3)$ is

2 x + 3 y = \sqrt{1} 3

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3 x + 3 y = 13

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2 x + 3 y = 13

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3 x + 3 y = \sqrt{1} 3

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Solution

The correct option is C $2 x + 3 y = 13$
Equation of Tangent to circle $x^{2} + y^{2} = r^{2}$ passing through point $(x_{1}, y_{1})$ is
$x x_{1} + y y_{1} = r^{2}$

Equation of tangent to given circle is passing through (2,3) is $2 x + 3 y = 13$

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