Question

The equation of tangent to the curve $y=e^{-\left|x\right|}$ at the point where the curve cuts the line $x=1$ is

• A. $x+y=e$
• B. $e(x+y)=1$
• C. $y+ex=1$
• D. none of these

Answer 1

The correct option is D none of these

Substituting $x=1$ in $y=e^{-\left|x\right|}$, we get $y=\frac{1}{e}$
Slope at point $(1,\frac{1}{e})$ is
$\frac{dy}{dx}=-\frac{1}{e}$
Hence equation of tangent is
$y-\frac{1}{e}=-\frac{1}{e}(x-1)ey+x=2$