The equation of tangent to the curve y - x 3-2 x -6 which is perpendicular to the line x -14 y -4-0 is -A- 14 x - y -22-0B- 14 x-y-18-0C- 14 x-y-5-0D- 14 x - y -1-0

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Equation of Pair of Tangents: Hyperbola

The equation ...

Question

The equation of tangent to the curve y = x³ + 2x + 6 which is perpendicular to the line x + 14y + 4 = 0 is :

14x- y + 22 = 0

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14x- y + 18 = 0

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14x -y + 1= 0

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14x - y + 5 = 0

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Solution

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Similar questions

L_{1} : \frac{x - 1}{2} = \frac{y}{- 2} = \frac{z + 2}{- 1}

L_{2} : \frac{x + 3}{8} = \frac{y - 4}{1} = \frac{z}{- 4}

y = x^{3} + 2 x - 4

x + 14 y + 3 = 0.

x^{2} + y^{2} - 14 x - 6 y - 6 = 0

3 x^{2} + 10 xy + 8 y^{2} + 14 x + 22 y + 7 = 0

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