The equation of tangent to the ellipse $4 x^{2} + 9 y^{2} = 36$ at $(3, - 2) i s$

2 x - 3 y = 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 x - 2 y = 13

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + y = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - y = 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 x - 3 y = 6$
The equation of tangent at $(x_{1}, y_{1})$ to the ellipse $4 x^{2} + 9 y^{2} = 36$ is $4 x x_{1} + 9 y y_{1} = 36$ ......(1).
Here $x_{1} = 3, y_{1} = - 2$ .
Then the equaiton of the tangent will be $4 x .3 + 9 y . (- 2) = 36$ or, $2 x - 3 y = 6$ .

Suggest Corrections

Similar questions

x^{2} - y + 2 = 0

4 x^{2} + 9 y^{2} = 36

4 x^{2} + 9 y^{2} = 72

3 x - 2 y = 5

x + 2 y = 10,

x + 2 y = 6

2 x + y = 6,

(3, - 2)

4 x^{2} + 9 y^{2} = 36

Join BYJU'S Learning Program