Question

The equation of tangent to the parabola $y^2=6x$ at point $(6,6)$ is

• A. $2x+3y-30=0$
• B. $2x-y-6=0$
• C. $2y-x-6=0$
• D. $x+y-12=0$

Answer 1

The correct option is C $2y-x-6=0$

Given parabola,
$y^2=6x$
The equation of tangent at $(6,6)$ is
$T=0\Rightarrow y\cdot 6=6\left(\frac{x+6}{2}\right)\Rightarrow 12y=6x+36$

Hence, the required equation of tangent is
$2y-x-6=0$